Small exercise of batch replacement with VIM regular expression

Last time we used macro operation in VIM A series of similar codes are generated in batches from a line of code , The text is here

This time we use regular expressions to realize batch replacement

Post the last exercise first

stay GVIM Next , The contents of the following figure

Change to the following

And it is pointed out that , Use batch operation , You cannot type line by line

Before giving the implementation method , Given first VIM The meaning of various symbols in

Now back to that little exercise , Because we mainly use regular to replace , So let's copy and paste the first line

 In normal mode 
gg // Back to the first line 
yy // Copy the first line 
19p // Paste 19 Time 

Then it became like this

Before replacing , introduce VIM The way to replace

The replacement format is

:s/a/b/g   // take a Replace with b
   //s yes substitute,g yes global

We first gg Back to the first line , Then look and add g And no addition g The difference between

The command line executes the following

:s/1/aa/

You can see , Only the first of the first line 1 Turned into aa

Then execute the following

u //undo, Undo the last action 
:s/1/aa/g

You can see all in the first line at this time 1 It's all replaced by aa

Although add g Put the first line 1 All replaced with aa, But only the first line has been replaced , If multiple lines need to be replaced , We can't do this on every line , So it introduces %

Let's execute the following content to see what the result is

u // Undo the last action 
:%s/1/aa/

You can see the first in each line at this time 1 It's all replaced by aa

If we just want to replace a few lines , Can be % Change to range

:5,8s/1/aa/

At this time only 5-8 Yes 1 Has been replaced by

Because the content of our little exercise is not fixed , So we need to introduce another function

\=line(".")

This function means to get the line number , And you can add, subtract, multiply , If you want to add n, It only needs

\=ling(".")+n

Try it first , Put the first line 2 Change to line number ×10

:s/2/\=line(".") * 10/

First line 2 Success was replaced by 10

The preparations are over , The regular expression of batch change is given directly below

:%s/\d/\=line(".")/

:%s/\d$/\=line(".") + 1/

The result of executing the first instruction

Then the result of executing the second instruction

Be accomplished

Finally, let's talk about the meaning of these two instructions

First is the first instruction

:%s/\d/\=line(".")/

%s： Replace all lines 
\d： The first number 
\=line(".")： Get line number 

Second instruction

:%s/\d$/\=line(".") + 1/

%s： Replace all lines 
\d$： The last number ,$ Is a positional metacharacter , Indicates row position 
\=line(".") + 1： Get the line number and  + 1