Programmer interview golden code interview question 01.02. determine whether it is character rearrangement

Method or number counting

#include <iostream>
#include<string>
using namespace std;

class Solution {
    
public:
	bool CheckPermutation(string s1, string s2) {
    
		int charCount1[100] = {
     0 };// All use 0 To initialize 
		int charCount2[100] = {
     0 };// All use 0 To initialize 
		if (s1.length() != s2.length())
			return false;
		for(int i = 0; i < int(s1.length()); i++){
    
			charCount1[s1[i] - 'a']++;
			charCount2[s2[i] - 'a']++;
		}
		for (int i = 0; i < 100; i++){
    // Here it is. 100 Used to be s1 The length of , Next time, the object and operation should be written clearly 
			if (abs(charCount1[i] - charCount2[i])>0){
    
				
				return false;
			}
				
		}
		return true;
	}
};
void main(){
    
	string a = "cuhv"; //C++ Much stricter , Double quotes represent strings 、 Single quotation marks indicate the character 
	string c = "cuvs";
	Solution object_f;
	bool b = object_f.CheckPermutation(a,c);
	cout << b << endl;
}

They use bit operations in this problem 、hash surface 、 Sort it .