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BT.656 interface rate
2022-07-22 00:51:00 【High man-made peak 168】
720p It's a video display format . Letter p Scan line by line (progressive scan), Numbers 720 In the horizontal direction 720 Scanning lines . Usually 720p The resolution of the picture is 1280×720, Generally, it can also be called HD (HD). But in some cases , Such as iPod Touch 4, Its 720P Video recording does not mean 1280×720(16:9), It is 960×720(4:3), Therefore, it is not indicated that HD Of 720P Filming doesn't always mean 1280×720(16:9).
Standard system Total scan line Image area scan line Total horizontal pixels Image area horizontal pixels sampling frequency
1080P / 60Hz 1125 1080 2200 1920 148.5MHz
1080P / 50Hz 1125 1080 2640 1920 148.5MHz
1080I / 60Hz 1125 1080 2200 1920 74.25MHz
1080I / 50Hz 1125 1080 2640 1920 74.25MHz
720P / 60Hz 750 720 1650 1280 74.25MHz
720P / 50Hz 750 720 1980 1280 74.25MHz
The basic concept of digital video comes from analog video . For analog video, we can understand this :
Video can be decomposed into several basic viewpoints ( Pixels ), Each pixel has its own color information , On the screen, print out these points by row and column with an electron gun , It forms a complete picture , Continuous shooting , The delay characteristic of human eyes can be used to display “ dynamic ” Image .
Analog bandwidth : Also known as “ Dot clock ”, Refers to the number of pixels scanned per second , That is, the sum of frequency points displayed on each scan line in unit time , In the analog video with MHz In units of .
for example ,720P/60Hz Analog bandwidth = 1650 * 750 * 60 = 74.25MHz It means that each clock should transmit 74.25M Analog video pixels . Empathy 1080P60 The point clock of is 148.5MHz.
But in digital video, every pixel is made of 3 Two different colors to represent , Each color is transmitted by a certain number of bits , So we usually use bps To represent digital bandwidth , If the RGB transmission , Use... For each color 1 Bytes to output , Then the digital bandwidth of the video is :
Digital BandWidth = Analog bandwidth * 8bit * 3 = 1.782Gbps It means to transmit every second 1.782 G Bit data .
1782 / 24 = 74.25
2640 * 1125 = 2970000 * 50 = 148500000 * 8 * 3 = 3564000000 = 3.564 Gbps
2200 * 1125 = 2475000 * 60 = 148500000
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